Gen I: Ta có: 2A + 3G= 3900 (1)
A mạch=15%, T mạch=25% => A gen = T gen =40% => G gen = X gen=60%
=> A/G = 4/6 = 2/3 => A=4/6 G(2)
Từ 1 và 2 suy ra 8/6G + 3G=3900 => G=X=900; A=T=600
Gen II: N gen = 2550*2/3,4 = 1500 nucleotit
mạch 2: T=2A, G=3A, X=4A
Theo nguyên tắc bổ sung: A mạch 1 = T mạch...
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